MockTests.ORG साइन इन

Chemical Thermodynamics Mock Tests

45 questions available

Chemical Thermodynamics Mock Test 1

Questions: 30

Chemical Thermodynamics Mock Test 2

Questions: 15

नमूना प्रश्न

JEE Main Chemistry
Given: C(s) + O₂(g) → CO₂(g), ΔH = -393.5 kJ; 2CO(g) + O₂(g) → 2CO₂(g), ΔH = -566.0 kJ. The enthalpy of formation of CO(g) is:
A -110.0 kJ/mol
B -283.0 kJ/mol
C -393.5 kJ/mol
D -676.5 kJ/mol
JEE Main Chemistry
At what temperature will the reaction be at equilibrium if ΔH = −40.0 kJ/mol and ΔS = −80.0 J/(mol·K)? (Assume ΔH and ΔS are temperature independent)
A 250 K
B 500 K
C 400 K
D 375 K
NEET Chemistry
For the reaction N₂(g) + 3H₂(g) → 2NH₃(g), the correct statement about entropy change is:
A ΔS is positive
B ΔS is negative
C ΔS = 0
D ΔS cannot be predicted
NEET Chemistry
For a reaction to be spontaneous at all temperatures, which combination of ΔH and ΔS must hold?
A ΔH < 0 and ΔS < 0
B ΔH > 0 and ΔS > 0
C ΔH < 0 and ΔS > 0
D ΔH > 0 and ΔS < 0
JEE Main Chemistry
The entropy change (ΔS) for the vaporization of a liquid is 108 J K⁻¹ mol⁻¹. If its enthalpy of vaporization is 30.8 kJ mol⁻¹, the boiling point of the liquid is:
A 285.2 K
B 285.2°C
C 308 K
D 273 K
JEE Main Chemistry
At what temperature will the reaction 2NO(g) + O₂(g) → 2NO₂(g) be at equilibrium if ΔH = −114.2 kJ/mol and ΔS = −146 J/(mol·K)?
A 392 K
B 456 K
C 782 K
D 1140 K
JEE Main Chemistry
The enthalpy of neutralization of a strong acid by a strong base is −57.1 kJ/mol. The enthalpy of neutralization of HCN by NaOH will be:
A Less than −57.1 kJ/mol (more negative)
B Exactly −57.1 kJ/mol
C Greater than −57.1 kJ/mol (less negative)
D Zero
JEE Main Chemistry
For a reaction at 298 K, ΔH = −92.0 kJ/mol and ΔS = −198 J/(mol·K). The reaction will be spontaneous at:
A All temperatures
B Only at temperatures below 465 K
C Only at temperatures above 465 K
D Only at 298 K

टिप्पणियाँ

0/2000

अभी तक कोई टिप्पणी नहीं। अपने विचार साझा करने वाले पहले व्यक्ति बनें!