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Modern Physics Atomic Physics Mock Tests

7 questions available

Modern Physics Atomic Physics Mock Test 1

Questions: 7

नमूना प्रश्न

JEE Advanced Physics
In a Bohr hydrogen atom, an electron transitions from the n = 3 level to the n = 1 level. The wavelength of the emitted photon is (Rydberg constant R = 1.097 × 10⁷ m⁻¹):
A 102.6 nm
B 656.3 nm
C 121.6 nm
D 365.0 nm
JEE Advanced Physics
An electron and a photon both have de Broglie wavelength lambda. The ratio of the kinetic energy of the electron to the energy of the photon is:
A 2*m*c*lambda/h
B h/(2*m*c*lambda)
C m*c*lambda/h
D 2*h/(m*c*lambda)
JEE Advanced Physics
A de Broglie wavelength of an electron is equal to the wavelength of a photon. If the kinetic energy of the electron is K, the energy of the photon is:
A sqrt(K*(K + 2mc^2))
B K
C K^2/(2mc^2)
D mc^2
JEE Advanced Physics
An electron in a hydrogen atom makes a transition from n = 4 to n = 2. The wavelength of the emitted photon is (Rydberg constant R = 1.097 x 10^7 m^-1):
A 486 nm
B 434 nm
C 656 nm
D 365 nm
JEE Advanced Physics
In a hydrogen atom, an electron transitions from the n = 4 energy level to the n = 2 energy level. The wavelength of the emitted photon is related to the Rydberg constant R by:
A 1/lambda = (3/16)R
B 1/lambda = (1/4)R
C 1/lambda = (7/144)R
D 1/lambda = R
JEE Advanced Physics
In a Bohr hydrogen atom, an electron transitions from the nth orbit to the ground state, emitting a photon of wavelength 102.6 nm. The value of n is:
A 1
B 2
C 3
D 4
JEE Advanced Physics
A hydrogen atom in the ground state absorbs a photon of energy 12.09 eV. The principal quantum number of the excited state is (ionization energy of hydrogen = 13.6 eV):
A 3
B 2
C 4
D 5

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