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Thermodynamics & Kinetic Theory Mock Tests

66 questions available

Thermodynamics & Kinetic Theory Mock Test 1

Questions: 30

Thermodynamics & Kinetic Theory Mock Test 2

Questions: 30

Thermodynamics & Kinetic Theory Mock Test 3

Questions: 6

नमूना प्रश्न

BITSAT Physics
One mole of an ideal diatomic gas (γ = 7/5) at pressure P and volume V is expanded isothermally to volume 2V, then cooled at constant volume back to pressure P. The magnitude of heat extracted during the constant-volume process is:
A nRT ln 2
B PV/2
C 5PV/4
D 5PV/2
BITSAT Physics
One mole of an ideal diatomic gas undergoes a cyclic process ABCA: AB is isobaric at pressure P from volume V to 2V, BC is adiabatic to volume 4V, and CA is isochoric back to state A. If γ = 7/5, the net work done by the gas in the cycle is:
A PV(1 − 2/γ − 1)/(γ − 1)
B PV × 2^(1−γ)/(γ − 1)
C PV(1 − 2^(1−γ))/(γ − 1)
D PV/γ
JEE Advanced Physics
A Carnot engine operates between temperatures T_H = 600 K and T_C = 300 K. It absorbs 3000 J of heat from the hot reservoir per cycle. The engine is now reversed and operated as a refrigerator between the same temperatures. If the refrigerator absorbs 1500 J from the cold reservoir, the work input required is:
A 1500 J
B 1000 J
C 500 J
D 2000 J
BITSAT Physics
Two moles of an ideal-gas at 300 K exert a pressure of 10⁵ Pa. What is the volume occupied by the gas? (Take R = 8.314 J/mol·K)
A 49.9 L
B 24.9 L
C 99.8 L
D 12.5 L
BITSAT Physics
An ideal gas undergoes an adiabatic expansion. If the volume doubles, the ratio of final to initial temperature is:
A 2^(1-gamma)
B 2^(gamma-1)
C 2^(-gamma)
D 2^(gamma+1)
BITSAT Physics
An ideal gas undergoes an isobaric process. If the temperature increases from T to 2T, the ratio of final to initial volume is:
A 2
B 1/2
C 4
D 1
BITSAT Physics
A Carnot engine operates between reservoirs at 500 K and 300 K. It absorbs 2000 J of heat from the hot reservoir per cycle. If the engine cycle time is reduced to half while maintaining the same reservoir temperatures, the power output:
A doubles
B halves
C remains the same
D quadruples
JEE Advanced Physics
A gas mixture contains 1 mole of a monoatomic gas (C_v = 3R/2) and 1 mole of a diatomic gas (C_v = 5R/2) at temperatures T_1 and T_2 respectively. They are mixed adiabatically in a rigid container. The final equilibrium temperature is:
A (3*T_1 + 5*T_2)/8
B (T_1 + T_2)/2
C (5*T_1 + 3*T_2)/8
D (2*T_1 + 3*T_2)/5

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