MockTests.ORG Sign in

Magnetic Effects & EMI Mock Tests

95 questions available

Magnetic Effects & EMI Mock Test 1

Questions: 30

Magnetic Effects & EMI Mock Test 2

Questions: 30

Magnetic Effects & EMI Mock Test 3

Questions: 30

Magnetic Effects & EMI Mock Test 4

Questions: 5

Sample Questions

BITSAT Physics
A long straight wire carries current I. A square loop of side a carrying current I is placed at distance d from the wire with its plane coplanar with the wire. The net force on the loop is:
A Always zero
B Always toward the wire
C Always away from the wire
D Non-zero and depends on current directions
JEE Advanced Physics
A long straight wire carries current I. A rectangular loop of sides a and b (a parallel to the wire) is placed at distance r from the wire in the same plane. The loop is pulled away from the wire with constant velocity v. The induced EMF in the loop is:
A μ₀Iabv/(2πr(r+a))
B μ₀Iav/(2π(r+a))
C μ₀Ibv/(2πr)
D μ₀Iabv/(2πr²)
BITSAT Physics
A particle of mass m and charge q enters a region of uniform magnetic field B with velocity v perpendicular to B. The particle moves in a circular path of radius R. If the charge is doubled and the mass is halved, the new radius of the circular path is:
A R/4
B R/2
C 2R
D R/8
BITSAT Physics
A long solenoid has n turns per unit length and carries current I. A circular loop of radius R and resistance R_res is placed coaxially inside the solenoid. If the current in the solenoid increases at a constant rate dI/dt, the induced current in the loop is:
A μ₀nπR²(dI/dt)/R_res, opposite to solenoid current direction
B μ₀nπR²(dI/dt)/R_res, in the same direction as solenoid current
C 2nπR(dI/dt)/R_res
D nπR(dI/dt)/R_res
JEE Advanced Physics
An electron and a proton enter a uniform magnetic field perpendicularly with the same kinetic energy. The ratio of the radii of their circular paths r_e/r_p is (mass of electron = m_e, mass of proton = m_p, charge magnitude = e):
A sqrt(m_e/m_p)
B sqrt(m_p/m_e)
C m_e/m_p
D m_p/m_e
BITSAT Physics
A conducting rod of length L moves with velocity v perpendicular to a uniform magnetic field B. The rod is part of a circuit with resistance R. The power dissipated in the resistor when an external force F pulls the rod at constant velocity is:
A F²R/B²L²
B FB²L²/R
C F²R²/B²L²
D FB/RL
BITSAT Physics
A series LCR circuit has L = 4 H and C = 25 μF. The resonant frequency of the circuit is:
A 100 Hz
B 50 Hz
C 200 Hz
D 25 Hz
BITSAT Physics
A conducting rod of length L slides without friction on horizontal conducting rails connected by a resistor R. A uniform magnetic field B is directed vertically downward. The rod is pulled by a constant force F. The terminal velocity of the rod is:
A B²L²/(FR)
B BL/(FR)
C FR/(B²L²)
D F/(BRL)

Comments

0/2000

No comments yet. Be the first to share your thoughts!