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Mechanics SHM Mock Tests

15 questions available

Mechanics SHM Mock Test 1

Questions: 15

Sample Questions

JEE Advanced Physics
A block of mass m is attached to two springs of spring constants k1 = 2k and k2 = k in parallel on a frictionless surface. The period of oscillation is T. What is the period if the same springs are connected in series?
A T * 3/sqrt(2)
B T * sqrt(2)/3
C T * sqrt(3)
D T/3
JEE Advanced Physics
A simple pendulum of length L has period T on Earth. If the same pendulum is taken to a planet where the gravitational acceleration is g/4, the new period is:
A 2T
B T/2
C T sqrt(2)
D T/4
JEE Advanced Physics
A simple pendulum of length L has a bob of mass m and charge q. A horizontal uniform electric field E exists in the region. The new time period of small oscillations is:
A 2*pi*sqrt(L/g_eff) where g_eff = sqrt(g^2 + (qE/m)^2)
B 2*pi*sqrt(L/g)
C 2*pi*sqrt(L/(g + qE/m))
D 2*pi*sqrt(L/(g - qE/m))
JEE Advanced Physics
A particle executes SHM with amplitude A. The ratio of its maximum speed to its maximum acceleration is:
A 1/omega
B omega
C A
D A*omega
JEE Advanced Physics
A particle of mass m moves in one dimension under a potential V(x) = αx⁴ where α > 0. For oscillations about x = 0 with amplitude A, the period of oscillation T is proportional to:
A 1/A
B 1/A²
C 1/√A
D A
JEE Advanced Physics
A simple pendulum of length L has period T when oscillating in air. The bob is a solid sphere of density ρ. When the bob is completely immersed in a liquid of density ρ/3, the new period T_new is approximately:
A T√(3/2)
B T√(2/3)
C T/2
D T√2
JEE Advanced Physics
A simple pendulum of length L has a period T on Earth. If the pendulum is taken to a height h above the Earth surface where the gravitational acceleration becomes (2/3)g, its new period is:
A T times sqrt(2)/sqrt(3)
B T times 2
C T times sqrt(3/2)
D T times sqrt(3)
JEE Advanced Physics
A simple pendulum of length L and mass m has a period T_0 in a stationary frame. The pendulum is now placed in an elevator accelerating upward with acceleration a = g/3. The new period T is:
A T_0 sqrt(3/4)
B T_0 sqrt(4/3)
C T_0/2
D 2T_0

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